Web6 feb. 2024 · Show that BC ∥QR . Using Theorem 6.1, prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side. (Recall that you Fig. 6.20 have proved it in Class IX). In the figure, ABC … WebIn the given figure , if ∠BAC=90 ∘ and AD⊥BC . Then , A BD.CD=BC 2 B AB.AC=BC 2 C BD.CD=AD 2 D AB.AC=AD 2 Medium Solution Verified by Toppr Correct option is C) In ΔADB and ΔADC , ∠BDA=∠ADC=90 ∘ [Given] ∠B=∠DAC=(90 ∘−C) ∴ΔADB∼ΔCDA [ By AA similarity criterion] ⇒ CDAD= CAAB= DADB ∴AD 2=BD⋅CD Was this answer helpful? 0 0 …
In the figure, ABC is a right angled triangle and BAC = 90°. If AD=BC …
Web∠A = 90° AD ⊥ BC at D. AB = 12 cm. AC = 16 cm. Concept used: Pythagoras' theorem … WebAlso, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50° We have to find the measure of ∠ACD. By … cyclopentanone ph
[Solved] In a ΔABC, ∠BAC = 90° and AD is perpendic - Testbook
Web17 apr. 2024 · Best answer ∠CAB = 90° and AD ⊥ BC If AC = 75 cm, AB = 1 m or 100 cm, BC = 1.25 m or 125 cm ∠BDA = ∠BAC = 90° ∠DBA = ∠CBA [common angles] By AA ∆BDA ~ ∆BAC And, ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise … Web26 aug. 2024 · Best answer (c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, … Web∠A = 90° AD ⊥ BC at D AB = 12 cm AC = 16 cm Concept used: Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides. Calculation: AB 2 + AC 2 = BC 2 ⇒ 12 2 + 16 2 = BC 2 ⇒ 144 + 256 = BC 2 ⇒ 400 = BC 2 ⇒ 20 = BC Now, using similarity of triangle ABC and DBA. rakka syrien heute